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Acedeal
November 13th, 2003, 05:24
A car is travelling at a uniform speed.
The driver sees a milestone showing a 2-digit number. After travelling for an hour the driver sees another milestone with the same digits in reverse order. After another hour the driver sees another milestone containing the same two digits as in the first one but the two digits separated by a zero(0).
What is the speed of the car?

Panda
November 13th, 2003, 06:51
45 mph :mrgreen:

The milestones were 16, 61, and 106.

Here's how I got that if anyone is curious.
One way to represent a 2 digit number is by 10a+b
After the first hour since the digits are reverse the second mile stone can be represented by 10b+a. That means the car has travelled a distance of 9(b-a) in that hour. ((10b+a)-(10a+b))
The third milestone shows 100a+b. So now the car has travelled a distance of 9(11a-b). You get this by doing the same thing I did before.

Now we have...
9(11a-b)=9(b-a)
or...b=6a

Since a and b are both integers, b=6 and a=1. Thus giving us the previously mentioned milestones.